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Duplicate an existing app and adding more features and functions

8 freelancer chào giá trung bình$192 cho công việc này

(264 Nhận xét)
8.8
simk33

Hi, I will create application according to your mentioned requirements. I have 2+years of experience in application development and worked on many projects. Let's connect in chat for further discussion.

$250 AUD trong 10 ngày
(27 Nhận xét)
5.2
ismailmousa8387

How are you? I can build you app. Thank you for checking my bid. I understand your needs and I think I can do it. If you hire me, I will do my best for you. I hope you would contact me and discuss details. Thank you.

$200 AUD trong 7 ngày
(14 Nhận xét)
4.9
wadielnatrontv

Hi there , How are you? This is Qandil I am web developer, having over 3 years of experience on freelancer . I can work on your project to deliver you according to the requirements. For more discussion on the project , Thêm

$250 AUD trong 10 ngày
(5 Nhận xét)
3.3
mrehman11068

Hi, I have read the description of your project. I can develop you this app as per your needs and requirements. I have over 3 years of experience in android apps development. Following are few examples of my previous Thêm

$111 AUD trong 7 ngày
(6 Nhận xét)
3.7
hardikgpatel

Hello I am Hardik Patel, I have an experience of 3 years on working with Android native and Flutter Cross Platform application, I had work with Social Media Application, Product based application, hardware connectivity Thêm

$140 AUD trong 7 ngày
(1 Nhận xét)
1.0
ceceliangelia

Hello my name is Cecelia. I have read and understood all your initial requirements, and I feel, I would be the best choice for this project, I have more than 10 years of working experience in the industry. I am produc Thêm

$140 AUD trong 7 ngày
(0 Nhận xét)
0.0
Oakbells

Hello , I have checked out all your requirements existing application development and we can help you. We are a team having experience of 7+ years of experience in application building. I am part of a professional tea Thêm

$200 AUD trong 3 ngày
(0 Nhận xét)
0.0