Male Fashion

Đã Đóng Đã đăng vào 3 năm trước Thanh toán khi bàn giao
Đã Đóng Thanh toán khi bàn giao

This project UserFriendly Website when user can purchase Man Acesaries

This Project is make in Django

Django Python HTML JavaScript Thiết kế trang web

ID dự án: #28377416

Về dự án

9 đề xuất Dự án từ xa 3 năm trước đang mở

9 freelancer chào giá trung bình₹16802 cho công việc này

shadabkhan92

Hi https://www.freelancer.com/projects/python/need-freelance-Django-developer done similar tasks lets chat

₹25000 INR trong 7 ngày
(36 Nhận xét)
6.4
sanadiv

I can design your website the way you want it and reach your vision I will be working with high quality themes and plugins and all the integrated needed to optimize the look and functionality of your website Price is Thêm

₹12500 INR trong 3 ngày
(21 Nhận xét)
5.8
akashchopra00441

Hi!! Dear Client As a leading web design company in Kolkata, India, our web designing experts ensures that your website is search engine friendly, aesthetically appealing and user friendly. Our goal is to serve all cus Thêm

₹14000 INR trong 7 ngày
(0 Nhận xét)
0.0
banoshabbu7

Hello Sir We are from IT company And we have checked your project details regarding build a website in Django for Mens fashion. I can do create this website as per your requirement. If you are interested, do let us kno Thêm

₹25000 INR trong 7 ngày
(0 Nhận xét)
0.0
dishadn

Hello, Based on the requirements I can confidently make your project within your budget and time. I have experience in handling similar kind of projects with quick response.

₹15000 INR trong 6 ngày
(0 Nhận xét)
0.0
ArtsiomIodko

Hi I can help you with your project. I can start immediately. So chat with me to discuss your project

₹12500 INR trong 3 ngày
(1 Nhận xét)
0.0
nilpatel62

PYTHON Hi, My name is Nil Patel. I am a backend developer in Python-Django. I have professional experience in Backend Development with Database design, API Documentation, Requirement analysis, Research, and development Thêm

₹22222 INR trong 3 ngày
(0 Nhận xét)
0.0