# STAND ALONE POWER PLANT

I need a simulation for a stand alone power plant

The power plant comprises 6 sets of PV arrays of 9kwp each making a total of 54 kwp. Each array is made up of 3 parallel lines and 10 modules in series making a total of 30 modules.

Specification for module is as follows

Nominal P (mpp) = 300w

Voltage at mpp = [url removed, login to view]

Current at mpp = [url removed, login to view]

Open circuit voltage = [url removed, login to view]

Short circuit current = [url removed, login to view]

Module efficiency = 13.6 percent

Each of the 6 arrays is then connected to its individual dc to ac inverter. A total of six inverters are used. The specification for the dc to ac inverter is as follows.

On the INPUT SIDE

Max. DC power (@ cos &amp;#966; = 1) 10350 W

Max. DC voltage 700 V

MPP voltage range 333 V – 500 V

DC nominal voltage 350 V

Min. DC voltage / start voltage 333 V / 400 V

Max. input current / per string 31 A / 31 A

Number of MPP trackers / strings per MPP tracker 1 / 5

ON THE OUTPUT SIDE

AC nominal power (@ 230 V, 50 Hz) 10000 W

Max. AC apparent power 10000 VA

Nominal AC voltage; range 220, 230, 240 V; 180 V – 260 V

AC grid frequency; range 50, 60 Hz; –6 Hz, +5 Hz

Max. output current 44 A

Power factor (cos &amp;#966;) 0.8 leading ... 0.8 lagging

Phase conductors / connection phases / power balancing 1 / 1 / yes

On the output side of the inverters, there is an AC COUPLING. A three phase coupling where the output of the inverter is connected(2 arrays per phase) to keep it balanced. The AC coupling feeds the load directly and whatver the excess is gets fed to the batteries via BIDIRECTIONAL INVERTERS.

For this I want to use 12 INVERTER units… Each unit of inverter consists of 3 bidirectional inverters in parallel. SO for the 12 UNITs, I will need 36 bidirectional inverters in total.

The specification for the inverter is as follows

Nominal AC voltage (adjustable) 230 V (202 V – 253 V)

Nominal frequency (adjustable) 50 Hz / 60 Hz (45 Hz – 65 Hz)

Continuous AC power at 25 &deg;C / 45 &deg;C 5000 W / 4000 W

AC output power at 25 &deg;C for 30 min / 1 min / 3 s 6500 W / 8400 W / 12000 W

Nominal AC current / max. AC current (peak) 21.7 A / 120 A for 60 ms

THD output voltage / power factor (cos &amp;#966;) &lt; 3 % / –1 to +1

AC input (generator or grid)

AC input voltage (range) 230 V (172.5 V – 264.5 V)

AC input frequency (range) 50 Hz / 60 Hz (40 Hz – 70 Hz)

Max. input current (adjustable) / max. input power 56 A (0 A – 56 A) / 12.8 kW

Battery voltage (range) 48 V (41 V – 63 V)

Max. battery charging current / continuous charging current at 25 &deg;C 120 A / 100 A

Battery type / battery capacity (range) lead, NiCd / 100 – 10,000 Ah

EACH OF THE 12 INVERTER UNITS ARE ALL CONNECTED TO EACH PHASE OF THE AC COUPLING. AND EACH OF THE 12 INVERTERS ARE ALSO CONNECTED TO BATTERIES FOR STORAGE.

I HAVE 12 BATTERY UNIT AND EACH UNIT COMPRISES OF 12 BATTERIES IN SERIES EACH. It has a rating of 1104Ah at a discharge rate of ( C)&amp;#8260;20, and the voltage is 4V.

In order to get the DC system voltage of 48V, 12 batteries have to be connected in series, giving a total output voltage of 12V * 4V = 48V.

The current for the series of batteries will be 1104Ah as current in a series circuit does not change.

In order to get the capacity we need, there will have to be 12 of these series in parallel with each other giving a total capacity of 1104Ah * 12 = 13248Ah

I CAN IMAGINE THAT NOT EVERYTHING HERE IS COMPLETELY ATTAINABLE WITH MATLAB BUT I WOULD LIKE THE SIMULATION TO BE AS CLOSE AS POSSIBLE TO THIS. AND I WOULD LIKE TO GET A SUMMARY OF HOW THIS WAS ACHIEVED. Thank you.

Kĩ năng: Kĩ thuật điện, Matlab and Mathematica

Về Bên Thuê:
( 0 nhận xét ) London, United Kingdom

ID dự án: #1019862

## Được trao cho:

sincere41

I am doing a PhD and Photovoltaics and have a more than 4 years of research experience in the field. I am also proficient in Matlab and Simulink. Please check PM for details.

\$200 USD trong 7 ngày
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