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Convert Node.js API to ASP.net API

9 freelancer chào giá trung bình₹8617 cho công việc này

(196 Nhận xét)
8.1
aeromustechnolog

Hi there, I have gone through your requirement to design and develop an website So I'm perfectly able to do this Job and I assure you that will give you quality work in less than anticipating time. I've vast experienc Thêm

₹7000 INR trong 7 ngày
(5 Nhận xét)
2.4
pantadeveloperr3

Hello. I am *Panter* 100% Completion Rate!!! I am an expert of Web Development such as c#, nodejs, php(WP,CI,Cake..),javascript, html,css,.net,and so on. I have done these works for several years. "Correct implementat Thêm

₹7000 INR trong 7 ngày
(0 Nhận xét)
0.0
CodeAfrika

Hello, I am an Expert in software (Python, Node, & C#). Because of this, I feel confident to deliver this project. I have 7+ years experience. Kindly let us discuss details in the chat. Cheers.

₹8000 INR trong 4 ngày
(0 Nhận xét)
0.0
marwanadala4

I've vast experience with web development both front and backend and have expertise in HTML, PHP, .NET, jQuery, and have been working professionally for the last 5 years. i can transforme your Thêm

₹7000 INR trong 7 ngày
(0 Nhận xét)
0.0
Govindsing2520

I have 10 years of experience in software development Let's connect and discuss more about your requirements

₹7778 INR trong 5 ngày
(0 Nhận xét)
0.0
firuzammammadova

I have written a lot of API`s in ASP.NET , and because of i have a understanding of JavaScript and Nodejs, I am very well able to convert Node.js code to the Asp.Net. You can look at my projects at github: https://git Thêm

₹8000 INR trong 7 ngày
(0 Nhận xét)
0.0
mitulsrv9500

Hello I am Mitul Sarvaiya as ASP.NET Developer. As per your requirement i can convert your nodejs application to ASP.NET Web app. I having experience of 4 year. Ping me here for more info.

₹6667 INR trong 4 ngày
(0 Nhận xét)
0.0
emilyhelda16

i am already having experience in web api development with c# luna and entity framework so I am interested to work on this project

₹6111 INR trong 5 ngày
(0 Nhận xét)
0.0