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126285 private project for webous

Hi Val,

Ref: EFA Version '3' (minor upgrade)

1. the file '[url removed, login to view]' has been renamed to '[url removed, login to view]' This new file '[url removed, login to view]' has the prev. checklicense function as as well as the new 'calculate_payee' function

2. The function calculate_payee has been coded as well

as tested. I've send more details in an email to you.

The code will remain as is.

I've looked at your codes, function get_admin_paypal_address in the "[url removed, login to view]" file and also the [url removed, login to view] file which called it.

If you want miniman changes, you can include the [url removed, login to view]

file in your [url removed, login to view] file, and then call the

calculate_payee function within your 'get_admin_paypal_address' function. Then, unpack, and return it as array to the [url removed, login to view] file.

You can see a simple demo that i've created that calls the

'calculate_payee' function. Details in email.

3. Deadline - 3 days.

Please keep strictly to 3 days, and not more.

** I have received a lot of pressure from Harvey in the

previous 2 projects because they were not completed according to schedule.

So, please do this as a favor to me as I have done you a couple of favors in the prev. 2 projects, e.g. in releasing the funds to you when you requested.

Also, please provide daily report as well - even if it's a short 1 liner:

"script progressing fine - will be completed in 2 more days"

This will make Harvey very happy!

4. As usual, this will be a ghost-scripting project like the previous ver1 and ver2, i.e. we own the codes.

Look forward to your speedy response.

Regards,

Adrian

Kỹ năng: Bất kì công việc gì, MySQL, PHP

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Về Bên Thuê:
( 17 nhận xét ) Petaling Jaya, Malaysia

Mã Dự Án: #1872452

2 freelancer đang chào giá trung bình $100 cho công việc này

fahad61814

dear sir, i want to work on this project

$100 USD trong 10 ngày
(1 Đánh Giá)
1.0
Petruchek

will be done

$100 USD trong 3 ngày
(0 Đánh Giá)
0.0