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PHP Script


There is are multiple business meetings happening at the same time, with 100 companies. Each company with 1 person.

And 10 tables. So we expect 5 people each table (5 chairs pre table).

After 10 minutes (finish this round), they change their chair/table. And a person cannot see another one which he has already met in previous meeting.

I need all available combinations, based on the input of number of tables, chairs per table and companies. All possible rounds must be returned.

It cannot be partially solved, ok?


The result is the list of companies, by table, for every round. As many rounds as possible (remember that a company cannot meet another one which has already met).

Example: (8 participants, 3 tables with 3 chairs each).

participants = [c0,c1,c2,c3,c4,c5,c6,c7]

Round 1

table1 = [c0,c1,c2]

table2 = [c3,c4,c5]

table3 = [c6,c7]

Round 2

table1 = [c0,c3,c6]

table2 = [c1,c4,c7]

table3 = [c2,c5]

Invalid Round (discarded):

table1 = [c1,c0,c4] (1 and 0 already met in Round 1)

table 2 = [c3,c7,c2]

table 3 = [c5,c6]

Expected return:

result = [

'round1' =>[










'round-n' => [...]




Eventually, one table will have less participants. It would be good if this value is balanced.

Example.: (27 participants, 6 tables with 5 chairs each).

Instead of this: 5+5+5+5+5+2

Return this: 5+5+5+4+4+4

Kỹ năng: Thuật toán, Phân tích, Toán học, PHP

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Về Bên Thuê:
( 1 nhận xét ) Rio de Janeiro, Brazil

Mã Dự Án: #14838548

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