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PHP Script

SCENARIO:

There is are multiple business meetings happening at the same time, with 100 companies. Each company with 1 person.

And 10 tables. So we expect 5 people each table (5 chairs pre table).

After 10 minutes (finish this round), they change their chair/table. And a person cannot see another one which he has already met in previous meeting.

I need all available combinations, based on the input of number of tables, chairs per table and companies. All possible rounds must be returned.

It cannot be partially solved, ok?

----------------------------------------------

The result is the list of companies, by table, for every round. As many rounds as possible (remember that a company cannot meet another one which has already met).

Example: (8 participants, 3 tables with 3 chairs each).

participants = [c0,c1,c2,c3,c4,c5,c6,c7]

Round 1

table1 = [c0,c1,c2]

table2 = [c3,c4,c5]

table3 = [c6,c7]

Round 2

table1 = [c0,c3,c6]

table2 = [c1,c4,c7]

table3 = [c2,c5]

Invalid Round (discarded):

table1 = [c1,c0,c4] (1 and 0 already met in Round 1)

table 2 = [c3,c7,c2]

table 3 = [c5,c6]

Expected return:

result = [

'round1' =>[

[c0,c1,c2],

[c3,c4,c5],

[c6,c7]

],

[

[c0,c3,c6],

[c1,c4,c7],

[c2,c5]

],

'round-n' => [...]

...

];

---------------------------------------------------

Eventually, one table will have less participants. It would be good if this value is balanced.

Example.: (27 participants, 6 tables with 5 chairs each).

Instead of this: 5+5+5+5+5+2

Return this: 5+5+5+4+4+4

Kỹ năng: Thuật toán, Phân tích, Toán học, PHP

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Về Bên Thuê:
( 0 nhận xét ) Brazil

Mã Dự Án: #14838548

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