Đang Thực Hiện

Verilog Ethernet Tx/Rx - Repost

I am running a big project and am currently time constrained to implement the Ethernet connection.

This is a fairly easy project for someone with expertise in Verilog. The deliverables are as follows

-Verilog code to run on a Spartan 6 Atlys Board - (xc6slx45)

-simulation time diagrams (more details will be given to the winner)

- The code should be able to transmit and receive data at 100mbs (1Gbps support would be nice but not a must)

-Support a multicasting protocol (In that if I wanted to send data to 3 recepients out of 5 in the network, I should be able to do it easily)

-Support for broadcasting (be able to make the system send the data to all recepients in the network when needed)

-there are existing IPcores that offer a starting point and I would suggest that they be used as time is critical here.

some cores that can be used are

[url removed, login to view]://[url removed, login to view],ethernet_tri_mode

[url removed, login to view]://[url removed, login to view],ethmac

[url removed, login to view]://[url removed, login to view]

The final code should offer me a way of changing the sender and receiver address and also of using fake test data

Be able to peform checksum and CRC error checks

I need this done in less than a week as I believe its not much work for someone who is good in verilog

Kỹ năng: Verilog / VHDL

Xem thêm: i spartan, system verilog, spartan, RX, network simulation, network diagrams, Ethernet, receive ethernet verilog, simulation network, implement checksum, crc code, implement protocol, sender receiver code, sender receiver, crc verilog, simulation code network, implement protocol using, network simulation using code, code crc, ethernet using verilog, ethernet protocol verilog, project code network simulation using, crc checksum, send receive ethernet, verilog ethernet code

Về Bên Thuê:
( 0 nhận xét ) DAEGU, Korea, Republic of

Mã Dự Án: #4543483

Đã trao cho:

mahiza

Hired by the Employer

$250 USD trong 7 ngày
(0 Đánh Giá)
0.0